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Calculate the molar mass of tetraphosphorus decaoxide,P4O10,a corrosive substance which can be used as a drying agent.


A) 469.73 g/mol
B) 283.89 g/mol
C) 190.97 g/mol
D) 139.88 g/mol
E) 94.97 g/mol

F) A) and B)
G) None of the above

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Hydroxylamine nitrate contains 29.17 mass % N,4.20 mass % H,and 66.63 mass O.If its molar mass is between 94 and 98 g/mol,what is its molecular formula?


A) NH2O5
B) N2H4O4
C) N3H3O3
D) N4H8O2
E) N2H2O4

F) A) and E)
G) All of the above

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Lead(II) nitrate is a poisonous substance which has been used in the manufacture of special explosives and as a sensitizer in photography.Calculate the mass of lead in 139 g of Pb(NO3) 2.


A) 107 g
B) 90.8 g
C) 87.0 g
D) 83.4 g
E) 62.6 g

F) All of the above
G) C) and D)

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Terephthalic acid,used in the production of polyester fibers and films,is composed of carbon,hydrogen,and oxygen.When 0.6943 g of terephthalic acid was subjected to combustion analysis it produced 1.471 g CO2 and 0.226 g H2O.If its molar mass is between 158 and 167 g/mol,what is its molecular formula?


A) C4H6O7
B) C6H8O5
C) C7H12O4
D) C4H3O2
E) C8H6O4

F) C) and D)
G) A) and B)

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The formula CH3O0.5 is an example of an empirical formula.

A) True
B) False

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In a correctly balanced equation,the number of reactant molecules must equal the number of product molecules.

A) True
B) False

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You are provided with a 250 mL volumetric flask,deionized water and solid NaOH.How much NaOH should be weighed out in order to make 250.mL of 0.100 M solution?

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Aluminum oxide (used as an adsorbent or a catalyst for organic reactions) forms when aluminum reacts with oxygen. 4Al(s) + 3O2(g) \to 2Al2O3(s) A mixture of 82.49 g of aluminum (  Aluminum oxide (used as an adsorbent or a catalyst for organic reactions) forms when aluminum reacts with oxygen. 4Al(s) + 3O<sub>2</sub>(g)   \to  2Al<sub>2</sub>O<sub>3</sub>(s)  A mixture of 82.49 g of aluminum (   = 26.98 g/mol) and 117.65 g of oxygen (   = 32.00 g/mol) is allowed to react.What mass of aluminum oxide (   = 101.96 g/mol) can be formed? A) 155.8 g B) 200.2 g C) 249.9 g D) 311.7 g E) 374.9 g = 26.98 g/mol) and 117.65 g of oxygen (  Aluminum oxide (used as an adsorbent or a catalyst for organic reactions) forms when aluminum reacts with oxygen. 4Al(s) + 3O<sub>2</sub>(g)   \to  2Al<sub>2</sub>O<sub>3</sub>(s)  A mixture of 82.49 g of aluminum (   = 26.98 g/mol) and 117.65 g of oxygen (   = 32.00 g/mol) is allowed to react.What mass of aluminum oxide (   = 101.96 g/mol) can be formed? A) 155.8 g B) 200.2 g C) 249.9 g D) 311.7 g E) 374.9 g = 32.00 g/mol) is allowed to react.What mass of aluminum oxide (  Aluminum oxide (used as an adsorbent or a catalyst for organic reactions) forms when aluminum reacts with oxygen. 4Al(s) + 3O<sub>2</sub>(g)   \to  2Al<sub>2</sub>O<sub>3</sub>(s)  A mixture of 82.49 g of aluminum (   = 26.98 g/mol) and 117.65 g of oxygen (   = 32.00 g/mol) is allowed to react.What mass of aluminum oxide (   = 101.96 g/mol) can be formed? A) 155.8 g B) 200.2 g C) 249.9 g D) 311.7 g E) 374.9 g = 101.96 g/mol) can be formed?


A) 155.8 g
B) 200.2 g
C) 249.9 g
D) 311.7 g
E) 374.9 g

F) B) and C)
G) C) and E)

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For a sample consisting of 2.50 g of methane,CH4,calculate a.the number of moles of methane present. b.the total number of atoms present.

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a.0.156 mo...

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One mole of methane (CH4)contains a total of 3 ×\times 1024 atoms.

A) True
B) False

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Balance the following equation: C8H18O3(l) + O2(g) \to H2O(g) + CO2(g)


A) C8H18O3(l) + 8O2(g) \to 9H2O(g) + 8CO2(g)
B) C8H18O3(l) + 11O2(g) \to 9H2O(g) + 8CO2(g)
C) 2C8H18O3(l) + 22O2(g) \to 9H2O(g) + 16CO2(g)
D) C8H18O3(l) + 13O2(g) \to 18H2O(g) + 8CO2(g)
E) 2C8H18O3(l) + 17O2(g) \to 18H2O(g) + 16CO2(g)

F) B) and C)
G) A) and C)

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Aluminum will react with bromine to form aluminum bromide (used as an acid catalyst in organic synthesis) . Al(s) + Br2(l) \to Al2Br6(s) [unbalanced] How many moles of Al are needed to form 2.43 mol of Al2Br6?


A) 7.29 mol
B) 4.86 mol
C) 2.43 mol
D) 1.62 mol
E) 1.22 mol

F) B) and E)
G) None of the above

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Hydroxylamine nitrate contains 29.17 mass % N,4.20 mass % H,and 66.63 mass % O.Determine its empirical formula.


A) HNO
B) H2NO2
C) HN6O16
D) HN16O7
E) H2NO3

F) B) and C)
G) A) and C)

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Sulfur dioxide reacts with chlorine to produce thionyl chloride (used as a drying agent for inorganic halides) and dichlorine oxide (used as a bleach for wood,pulp and textiles) . SO2(g) + 2Cl2(g) \to SOCl2(g) + Cl2O(g) If 0.400 mol of Cl2 reacts with excess SO2,how many moles of Cl2O are formed?


A) 0.800 mol
B) 0.400 mol
C) 0.200 mol
D) 0.100 mol
E) 0.0500 mol

F) C) and D)
G) C) and E)

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Terephthalic acid,used in the production of polyester fibers and films,is composed of carbon,hydrogen,and oxygen.When 0.6943 g of terephthalic acid was subjected to combustion analysis it produced 1.471 g CO2 and 0.226 g H2O.What is its empirical formula?


A) C2H3O4
B) C3H4O2
C) C4H3O2
D) C5H12O4
E) C2H2O

F) B) and C)
G) A) and E)

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Calculate the molar mass of Ca(BO2) 2·6H2O.


A) 273.87 g/mol
B) 233.79 g/mol
C) 183.79 g/mol
D) 174.89 g/mol
E) 143.71 g/mol

F) D) and E)
G) B) and C)

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Calculate the molar mass of (NH4) 3AsO4.


A) 417.80 g/mol
B) 193.03 g/mol
C) 165.02 g/mol
D) 156.96 g/mol
E) 108.96 g/mol

F) A) and D)
G) A) and B)

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Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. 3Mg(s) + 2FeCl3(s) \to 3MgCl2(s) + 2Fe(s) A mixture of 41.0 g of magnesium (  Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. 3Mg(s) + 2FeCl<sub>3</sub>(s)   \to  3MgCl<sub>2</sub>(s) + 2Fe(s)  A mixture of 41.0 g of magnesium (   = 24.31 g/mol) and 175 g of iron(III) chloride (   = 162.2 g/mol) is allowed to react.Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete. A) Limiting reactant is Mg;67 g of FeCl<sub>3</sub> remain. B) Limiting reactant is Mg;134 g of FeCl<sub>3</sub> remain. C) Limiting reactant is Mg;104 g of FeCl<sub>3</sub> remain. D) Limiting reactant is FeCl<sub>3</sub>;2 g of Mg remain. E) Limiting reactant is FeCl<sub>3</sub>;87 g of Mg remain. = 24.31 g/mol) and 175 g of iron(III) chloride (  Magnesium (used in the manufacture of light alloys) reacts with iron(III) chloride to form magnesium chloride and iron. 3Mg(s) + 2FeCl<sub>3</sub>(s)   \to  3MgCl<sub>2</sub>(s) + 2Fe(s)  A mixture of 41.0 g of magnesium (   = 24.31 g/mol) and 175 g of iron(III) chloride (   = 162.2 g/mol) is allowed to react.Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete. A) Limiting reactant is Mg;67 g of FeCl<sub>3</sub> remain. B) Limiting reactant is Mg;134 g of FeCl<sub>3</sub> remain. C) Limiting reactant is Mg;104 g of FeCl<sub>3</sub> remain. D) Limiting reactant is FeCl<sub>3</sub>;2 g of Mg remain. E) Limiting reactant is FeCl<sub>3</sub>;87 g of Mg remain. = 162.2 g/mol) is allowed to react.Identify the limiting reactant and determine the mass of the excess reactant present in the vessel when the reaction is complete.


A) Limiting reactant is Mg;67 g of FeCl3 remain.
B) Limiting reactant is Mg;134 g of FeCl3 remain.
C) Limiting reactant is Mg;104 g of FeCl3 remain.
D) Limiting reactant is FeCl3;2 g of Mg remain.
E) Limiting reactant is FeCl3;87 g of Mg remain.

F) A) and D)
G) None of the above

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One mole of O2 has a mass of 16.0 g.

A) True
B) False

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Analysis of a white solid produced in a reaction between chlorine and phosphorus showed that it contained 77.44% chlorine and 22.56% phosphorus.What is its empirical formula?

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